Jaslyn has 30% as many stickers as Esther. Esther has 140% as many stickers as Raeann. If Esther gives 40 stickers to Raeann, both will then have an equal number of stickers. Find the average number of stickers the three of them have.

Jaslyn	Esther	Raeann
3x7	10x7
	7x10	5x10
21 u	70 u	50 u

30% = ³⁰₁₀₀ = ³₁₀
140% = ¹⁴⁰₁₀₀= ⁷₅

The number of stickers that Jaslyn has is repeated.  Make the number of stickers that Jaslyn has the same. LCM of 10 and 7 is 70.

	Esther	Raeann	Total
Before	70 u	50 u	120 u
Change	- 10 u	+ 10 u
After	60 u	60 u	120 u

Total number of stickers that Esther and Raeann have
= 70 u + 50 u
= 120 u

After Esther gives to Raeann, both of them will have the same number of stickers. 

The total number of stickers that Esther and Raeann have remains unchanged.

Number of stickers that each of them will have
= 120 u ÷ 2
= 60 u

Number of stickers that Esther gives to Raeann
= 70 u - 60 u
= 10 u

10 u = 40

1 u = 40 ÷ 10 = 4

Total number of stickers that three of them have
= 120 u + 21 u
= 141 u

Average number of stickers that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 4
= 188

Answer(s): 188