Tiffany has 30% as many stickers as Jaslyn. Jaslyn has 110% as many stickers as Jen. If Jaslyn gives 40 stickers to Jen, both will then have an equal number of stickers. Find the average number of stickers the three of them have.

Tiffany	Jaslyn	Jen
3x11	10x11
	11x10	10x10
33 u	110 u	100 u

30% = ³⁰₁₀₀ = ³₁₀
110% = ¹¹⁰₁₀₀= ¹¹₁₀

The number of stickers that Tiffany has is repeated.  Make the number of stickers that Tiffany has the same. LCM of 10 and 11 is 110.

	Jaslyn	Jen	Total
Before	110 u	100 u	210 u
Change	- 5 u	+ 5 u
After	105 u	105 u	210 u

Total number of stickers that Jaslyn and Jen have
= 110 u + 100 u
= 210 u

After Jaslyn gives to Jen, both of them will have the same number of stickers. 

The total number of stickers that Jaslyn and Jen have remains unchanged.

Number of stickers that each of them will have
= 210 u ÷ 2
= 105 u

Number of stickers that Jaslyn gives to Jen
= 110 u - 105 u
= 5 u

5 u = 40

1 u = 40 ÷ 5 = 8

Total number of stickers that three of them have
= 210 u + 33 u
= 243 u

Average number of stickers that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 8
= 648

Answer(s): 648