Xylia has 25% as many pens as Marion. Marion has 130% as many pens as Eva. If Marion gives 48 pens to Eva, both will then have an equal number of pens. Find the average number of pens the three of them have.

Xylia	Marion	Eva
1x13	4x13
	13x4	10x4
13 u	52 u	40 u

25% = ²⁵₁₀₀ = ¹₄
130% = ¹³⁰₁₀₀= ¹³₁₀

The number of pens that Xylia has is repeated.  Make the number of pens that Xylia has the same. LCM of 4 and 13 is 52.

	Marion	Eva	Total
Before	52 u	40 u	92 u
Change	- 6 u	+ 6 u
After	46 u	46 u	92 u

Total number of pens that Marion and Eva have
= 52 u + 40 u
= 92 u

After Marion gives to Eva, both of them will have the same number of pens. 

The total number of pens that Marion and Eva have remains unchanged.

Number of pens that each of them will have
= 92 u ÷ 2
= 46 u

Number of pens that Marion gives to Eva
= 52 u - 46 u
= 6 u

6 u = 48

1 u = 48 ÷ 6 = 8

Total number of pens that three of them have
= 92 u + 13 u
= 105 u

Average number of pens that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 8
= 280

Answer(s): 280