Tina has 25% as many pens as Hilda. Hilda has 130% as many pens as Yoko. If Hilda gives 36 pens to Yoko, both will then have an equal number of pens. Find the average number of pens the three of them have.

Tina	Hilda	Yoko
1x13	4x13
	13x4	10x4
13 u	52 u	40 u

25% = ²⁵₁₀₀ = ¹₄
130% = ¹³⁰₁₀₀= ¹³₁₀

The number of pens that Tina has is repeated.  Make the number of pens that Tina has the same. LCM of 4 and 13 is 52.

	Hilda	Yoko	Total
Before	52 u	40 u	92 u
Change	- 6 u	+ 6 u
After	46 u	46 u	92 u

Total number of pens that Hilda and Yoko have
= 52 u + 40 u
= 92 u

After Hilda gives to Yoko, both of them will have the same number of pens. 

The total number of pens that Hilda and Yoko have remains unchanged.

Number of pens that each of them will have
= 92 u ÷ 2
= 46 u

Number of pens that Hilda gives to Yoko
= 52 u - 46 u
= 6 u

6 u = 36

1 u = 36 ÷ 6 = 6

Total number of pens that three of them have
= 92 u + 13 u
= 105 u

Average number of pens that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 6
= 210

Answer(s): 210