Jade has 25% as many stickers as Abi. Abi has 130% as many stickers as Wendy. If Abi gives 12 stickers to Wendy, both will then have an equal number of stickers. Find the average number of stickers the three of them have.
Jade |
Abi |
Wendy |
1x13 |
4x13 |
|
|
13x4 |
10x4 |
13 u |
52 u |
40 u |
25% =
25100 =
14130% =
130100=
1310The number of stickers that Jade has is repeated. Make the number of stickers that Jade has the same. LCM of 4 and 13 is 52.
|
Abi |
Wendy |
Total |
Before |
52 u |
40 u |
92 u |
Change |
- 6 u |
+ 6 u |
|
After |
46 u |
46 u |
92 u |
Total number of stickers that Abi and Wendy have
= 52 u + 40 u
= 92 u
After Abi gives to Wendy, both of them will have the same number of stickers.
The total number of stickers that Abi and Wendy have remains unchanged.
Number of stickers that each of them will have
= 92 u ÷ 2
= 46 u
Number of stickers that Abi gives to Wendy
= 52 u - 46 u
= 6 u
6 u = 12
1 u = 12 ÷ 6 = 2
Total number of stickers that three of them have
= 92 u + 13 u
= 105 u
Average number of stickers that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 2
= 70
Answer(s): 70