Natalie has 30% as many buttons as Wendy. Wendy has 140% as many buttons as Hilda. If Wendy gives 60 buttons to Hilda, both will then have an equal number of buttons. Find the average number of buttons the three of them have.
Natalie |
Wendy |
Hilda |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of buttons that Natalie has is repeated. Make the number of buttons that Natalie has the same. LCM of 10 and 7 is 70.
|
Wendy |
Hilda |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of buttons that Wendy and Hilda have
= 70 u + 50 u
= 120 u
After Wendy gives to Hilda, both of them will have the same number of buttons.
The total number of buttons that Wendy and Hilda have remains unchanged.
Number of buttons that each of them will have
= 120 u ÷ 2
= 60 u
Number of buttons that Wendy gives to Hilda
= 70 u - 60 u
= 10 u
10 u = 60
1 u = 60 ÷ 10 = 6
Total number of buttons that three of them have
= 120 u + 21 u
= 141 u
Average number of buttons that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 6
= 282
Answer(s): 282