Jade has 25% as many erasers as Xylia. Xylia has 130% as many erasers as Hazel. If Xylia gives 60 erasers to Hazel, both will then have an equal number of erasers. Find the average number of erasers the three of them have.

Jade	Xylia	Hazel
1x13	4x13
	13x4	10x4
13 u	52 u	40 u

25% = ²⁵₁₀₀ = ¹₄
130% = ¹³⁰₁₀₀= ¹³₁₀

The number of erasers that Jade has is repeated.  Make the number of erasers that Jade has the same. LCM of 4 and 13 is 52.

	Xylia	Hazel	Total
Before	52 u	40 u	92 u
Change	- 6 u	+ 6 u
After	46 u	46 u	92 u

Total number of erasers that Xylia and Hazel have
= 52 u + 40 u
= 92 u

After Xylia gives to Hazel, both of them will have the same number of erasers. 

The total number of erasers that Xylia and Hazel have remains unchanged.

Number of erasers that each of them will have
= 92 u ÷ 2
= 46 u

Number of erasers that Xylia gives to Hazel
= 52 u - 46 u
= 6 u

6 u = 60

1 u = 60 ÷ 6 = 10

Total number of erasers that three of them have
= 92 u + 13 u
= 105 u

Average number of erasers that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 10
= 350

Answer(s): 350