Ivory has 30% as many stickers as Eva. Eva has 110% as many stickers as Marion. If Eva gives 60 stickers to Marion, both will then have an equal number of stickers. Find the average number of stickers the three of them have.
Ivory |
Eva |
Marion |
3x11 |
10x11 |
|
|
11x10 |
10x10 |
33 u |
110 u |
100 u |
30% =
30100 =
310110% =
110100=
1110The number of stickers that Ivory has is repeated. Make the number of stickers that Ivory has the same. LCM of 10 and 11 is 110.
|
Eva |
Marion |
Total |
Before |
110 u |
100 u |
210 u |
Change |
- 5 u |
+ 5 u |
|
After |
105 u |
105 u |
210 u |
Total number of stickers that Eva and Marion have
= 110 u + 100 u
= 210 u
After Eva gives to Marion, both of them will have the same number of stickers.
The total number of stickers that Eva and Marion have remains unchanged.
Number of stickers that each of them will have
= 210 u ÷ 2
= 105 u
Number of stickers that Eva gives to Marion
= 110 u - 105 u
= 5 u
5 u = 60
1 u = 60 ÷ 5 = 12
Total number of stickers that three of them have
= 210 u + 33 u
= 243 u
Average number of stickers that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 12
= 972
Answer(s): 972