Victoria has 25% as many buttons as Anna. Anna has 130% as many buttons as Jane. If Anna gives 42 buttons to Jane, both will then have an equal number of buttons. Find the average number of buttons the three of them have.
Victoria |
Anna |
Jane |
1x13 |
4x13 |
|
|
13x4 |
10x4 |
13 u |
52 u |
40 u |
25% =
25100 =
14130% =
130100=
1310The number of buttons that Victoria has is repeated. Make the number of buttons that Victoria has the same. LCM of 4 and 13 is 52.
|
Anna |
Jane |
Total |
Before |
52 u |
40 u |
92 u |
Change |
- 6 u |
+ 6 u |
|
After |
46 u |
46 u |
92 u |
Total number of buttons that Anna and Jane have
= 52 u + 40 u
= 92 u
After Anna gives to Jane, both of them will have the same number of buttons.
The total number of buttons that Anna and Jane have remains unchanged.
Number of buttons that each of them will have
= 92 u ÷ 2
= 46 u
Number of buttons that Anna gives to Jane
= 52 u - 46 u
= 6 u
6 u = 42
1 u = 42 ÷ 6 = 7
Total number of buttons that three of them have
= 92 u + 13 u
= 105 u
Average number of buttons that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 7
= 245
Answer(s): 245