Kimberly has 25% as many buttons as Pamela. Pamela has 130% as many buttons as Julie. If Pamela gives 42 buttons to Julie, both will then have an equal number of buttons. Find the average number of buttons the three of them have.

Kimberly	Pamela	Julie
1x13	4x13
	13x4	10x4
13 u	52 u	40 u

25% = ²⁵₁₀₀ = ¹₄
130% = ¹³⁰₁₀₀= ¹³₁₀

The number of buttons that Kimberly has is repeated.  Make the number of buttons that Kimberly has the same. LCM of 4 and 13 is 52.

	Pamela	Julie	Total
Before	52 u	40 u	92 u
Change	- 6 u	+ 6 u
After	46 u	46 u	92 u

Total number of buttons that Pamela and Julie have
= 52 u + 40 u
= 92 u

After Pamela gives to Julie, both of them will have the same number of buttons. 

The total number of buttons that Pamela and Julie have remains unchanged.

Number of buttons that each of them will have
= 92 u ÷ 2
= 46 u

Number of buttons that Pamela gives to Julie
= 52 u - 46 u
= 6 u

6 u = 42

1 u = 42 ÷ 6 = 7

Total number of buttons that three of them have
= 92 u + 13 u
= 105 u

Average number of buttons that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 7
= 245

Answer(s): 245