Gem has 30% as many coins as Sabrina. Sabrina has 140% as many coins as Victoria. If Sabrina gives 50 coins to Victoria, both will then have an equal number of coins. Find the average number of coins the three of them have.
Gem |
Sabrina |
Victoria |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of coins that Gem has is repeated. Make the number of coins that Gem has the same. LCM of 10 and 7 is 70.
|
Sabrina |
Victoria |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of coins that Sabrina and Victoria have
= 70 u + 50 u
= 120 u
After Sabrina gives to Victoria, both of them will have the same number of coins.
The total number of coins that Sabrina and Victoria have remains unchanged.
Number of coins that each of them will have
= 120 u ÷ 2
= 60 u
Number of coins that Sabrina gives to Victoria
= 70 u - 60 u
= 10 u
10 u = 50
1 u = 50 ÷ 10 = 5
Total number of coins that three of them have
= 120 u + 21 u
= 141 u
Average number of coins that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 5
= 235
Answer(s): 235