Risa has 25% as many coins as Jaslyn. Jaslyn has 130% as many coins as Hilda. If Jaslyn gives 66 coins to Hilda, both will then have an equal number of coins. Find the average number of coins the three of them have.

Risa	Jaslyn	Hilda
1x13	4x13
	13x4	10x4
13 u	52 u	40 u

25% = ²⁵₁₀₀ = ¹₄
130% = ¹³⁰₁₀₀= ¹³₁₀

The number of coins that Risa has is repeated.  Make the number of coins that Risa has the same. LCM of 4 and 13 is 52.

	Jaslyn	Hilda	Total
Before	52 u	40 u	92 u
Change	- 6 u	+ 6 u
After	46 u	46 u	92 u

Total number of coins that Jaslyn and Hilda have
= 52 u + 40 u
= 92 u

After Jaslyn gives to Hilda, both of them will have the same number of coins. 

The total number of coins that Jaslyn and Hilda have remains unchanged.

Number of coins that each of them will have
= 92 u ÷ 2
= 46 u

Number of coins that Jaslyn gives to Hilda
= 52 u - 46 u
= 6 u

6 u = 66

1 u = 66 ÷ 6 = 11

Total number of coins that three of them have
= 92 u + 13 u
= 105 u

Average number of coins that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 11
= 385

Answer(s): 385