Cindy has 25% as many stickers as Eva. Eva has 130% as many stickers as Gem. If Eva gives 48 stickers to Gem, both will then have an equal number of stickers. Find the average number of stickers the three of them have.

Cindy	Eva	Gem
1x13	4x13
	13x4	10x4
13 u	52 u	40 u

25% = ²⁵₁₀₀ = ¹₄
130% = ¹³⁰₁₀₀= ¹³₁₀

The number of stickers that Cindy has is repeated.  Make the number of stickers that Cindy has the same. LCM of 4 and 13 is 52.

	Eva	Gem	Total
Before	52 u	40 u	92 u
Change	- 6 u	+ 6 u
After	46 u	46 u	92 u

Total number of stickers that Eva and Gem have
= 52 u + 40 u
= 92 u

After Eva gives to Gem, both of them will have the same number of stickers. 

The total number of stickers that Eva and Gem have remains unchanged.

Number of stickers that each of them will have
= 92 u ÷ 2
= 46 u

Number of stickers that Eva gives to Gem
= 52 u - 46 u
= 6 u

6 u = 48

1 u = 48 ÷ 6 = 8

Total number of stickers that three of them have
= 92 u + 13 u
= 105 u

Average number of stickers that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 8
= 280

Answer(s): 280