Linda has 30% as many coins as Vanessa. Vanessa has 140% as many coins as Victoria. If Vanessa gives 40 coins to Victoria, both will then have an equal number of coins. Find the average number of coins the three of them have.
Linda |
Vanessa |
Victoria |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of coins that Linda has is repeated. Make the number of coins that Linda has the same. LCM of 10 and 7 is 70.
|
Vanessa |
Victoria |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of coins that Vanessa and Victoria have
= 70 u + 50 u
= 120 u
After Vanessa gives to Victoria, both of them will have the same number of coins.
The total number of coins that Vanessa and Victoria have remains unchanged.
Number of coins that each of them will have
= 120 u ÷ 2
= 60 u
Number of coins that Vanessa gives to Victoria
= 70 u - 60 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Total number of coins that three of them have
= 120 u + 21 u
= 141 u
Average number of coins that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 4
= 188
Answer(s): 188