Xandra has 25% as many coins as Emily. Emily has 130% as many coins as Xylia. If Emily gives 36 coins to Xylia, both will then have an equal number of coins. Find the average number of coins the three of them have.
Xandra |
Emily |
Xylia |
1x13 |
4x13 |
|
|
13x4 |
10x4 |
13 u |
52 u |
40 u |
25% =
25100 =
14130% =
130100=
1310The number of coins that Xandra has is repeated. Make the number of coins that Xandra has the same. LCM of 4 and 13 is 52.
|
Emily |
Xylia |
Total |
Before |
52 u |
40 u |
92 u |
Change |
- 6 u |
+ 6 u |
|
After |
46 u |
46 u |
92 u |
Total number of coins that Emily and Xylia have
= 52 u + 40 u
= 92 u
After Emily gives to Xylia, both of them will have the same number of coins.
The total number of coins that Emily and Xylia have remains unchanged.
Number of coins that each of them will have
= 92 u ÷ 2
= 46 u
Number of coins that Emily gives to Xylia
= 52 u - 46 u
= 6 u
6 u = 36
1 u = 36 ÷ 6 = 6
Total number of coins that three of them have
= 92 u + 13 u
= 105 u
Average number of coins that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 6
= 210
Answer(s): 210