Marion has 30% as many stickers as Esther. Esther has 140% as many stickers as Hilda. If Esther gives 110 stickers to Hilda, both will then have an equal number of stickers. Find the average number of stickers the three of them have.

Marion	Esther	Hilda
3x7	10x7
	7x10	5x10
21 u	70 u	50 u

30% = ³⁰₁₀₀ = ³₁₀
140% = ¹⁴⁰₁₀₀= ⁷₅

The number of stickers that Marion has is repeated.  Make the number of stickers that Marion has the same. LCM of 10 and 7 is 70.

	Esther	Hilda	Total
Before	70 u	50 u	120 u
Change	- 10 u	+ 10 u
After	60 u	60 u	120 u

Total number of stickers that Esther and Hilda have
= 70 u + 50 u
= 120 u

After Esther gives to Hilda, both of them will have the same number of stickers. 

The total number of stickers that Esther and Hilda have remains unchanged.

Number of stickers that each of them will have
= 120 u ÷ 2
= 60 u

Number of stickers that Esther gives to Hilda
= 70 u - 60 u
= 10 u

10 u = 110

1 u = 110 ÷ 10 = 11

Total number of stickers that three of them have
= 120 u + 21 u
= 141 u

Average number of stickers that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 11
= 517

Answer(s): 517