Gabby has 30% as many beads as Tina. Tina has 140% as many beads as Mary. If Tina gives 50 beads to Mary, both will then have an equal number of beads. Find the average number of beads the three of them have.
Gabby |
Tina |
Mary |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of beads that Gabby has is repeated. Make the number of beads that Gabby has the same. LCM of 10 and 7 is 70.
|
Tina |
Mary |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of beads that Tina and Mary have
= 70 u + 50 u
= 120 u
After Tina gives to Mary, both of them will have the same number of beads.
The total number of beads that Tina and Mary have remains unchanged.
Number of beads that each of them will have
= 120 u ÷ 2
= 60 u
Number of beads that Tina gives to Mary
= 70 u - 60 u
= 10 u
10 u = 50
1 u = 50 ÷ 10 = 5
Total number of beads that three of them have
= 120 u + 21 u
= 141 u
Average number of beads that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 5
= 235
Answer(s): 235