Xuan has 30% as many beads as Barbara. Barbara has 140% as many beads as Joelle. If Barbara gives 100 beads to Joelle, both will then have an equal number of beads. Find the average number of beads the three of them have.
Xuan |
Barbara |
Joelle |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of beads that Xuan has is repeated. Make the number of beads that Xuan has the same. LCM of 10 and 7 is 70.
|
Barbara |
Joelle |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of beads that Barbara and Joelle have
= 70 u + 50 u
= 120 u
After Barbara gives to Joelle, both of them will have the same number of beads.
The total number of beads that Barbara and Joelle have remains unchanged.
Number of beads that each of them will have
= 120 u ÷ 2
= 60 u
Number of beads that Barbara gives to Joelle
= 70 u - 60 u
= 10 u
10 u = 100
1 u = 100 ÷ 10 = 10
Total number of beads that three of them have
= 120 u + 21 u
= 141 u
Average number of beads that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 10
= 470
Answer(s): 470