Hazel has 25% as many pens as Usha. Usha has 130% as many pens as Kimberly. If Usha gives 54 pens to Kimberly, both will then have an equal number of pens. Find the average number of pens the three of them have.
Hazel |
Usha |
Kimberly |
1x13 |
4x13 |
|
|
13x4 |
10x4 |
13 u |
52 u |
40 u |
25% =
25100 =
14130% =
130100=
1310The number of pens that Hazel has is repeated. Make the number of pens that Hazel has the same. LCM of 4 and 13 is 52.
|
Usha |
Kimberly |
Total |
Before |
52 u |
40 u |
92 u |
Change |
- 6 u |
+ 6 u |
|
After |
46 u |
46 u |
92 u |
Total number of pens that Usha and Kimberly have
= 52 u + 40 u
= 92 u
After Usha gives to Kimberly, both of them will have the same number of pens.
The total number of pens that Usha and Kimberly have remains unchanged.
Number of pens that each of them will have
= 92 u ÷ 2
= 46 u
Number of pens that Usha gives to Kimberly
= 52 u - 46 u
= 6 u
6 u = 54
1 u = 54 ÷ 6 = 9
Total number of pens that three of them have
= 92 u + 13 u
= 105 u
Average number of pens that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 9
= 315
Answer(s): 315