Diana has 25% as many stamps as Gem. Gem has 130% as many stamps as Anna. If Gem gives 48 stamps to Anna, both will then have an equal number of stamps. Find the average number of stamps the three of them have.
Diana |
Gem |
Anna |
1x13 |
4x13 |
|
|
13x4 |
10x4 |
13 u |
52 u |
40 u |
25% =
25100 =
14130% =
130100=
1310The number of stamps that Diana has is repeated. Make the number of stamps that Diana has the same. LCM of 4 and 13 is 52.
|
Gem |
Anna |
Total |
Before |
52 u |
40 u |
92 u |
Change |
- 6 u |
+ 6 u |
|
After |
46 u |
46 u |
92 u |
Total number of stamps that Gem and Anna have
= 52 u + 40 u
= 92 u
After Gem gives to Anna, both of them will have the same number of stamps.
The total number of stamps that Gem and Anna have remains unchanged.
Number of stamps that each of them will have
= 92 u ÷ 2
= 46 u
Number of stamps that Gem gives to Anna
= 52 u - 46 u
= 6 u
6 u = 48
1 u = 48 ÷ 6 = 8
Total number of stamps that three of them have
= 92 u + 13 u
= 105 u
Average number of stamps that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 8
= 280
Answer(s): 280