Gillian has 30% as many beads as Yoko. Yoko has 140% as many beads as Fanny. If Yoko gives 50 beads to Fanny, both will then have an equal number of beads. Find the average number of beads the three of them have.
Gillian |
Yoko |
Fanny |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of beads that Gillian has is repeated. Make the number of beads that Gillian has the same. LCM of 10 and 7 is 70.
|
Yoko |
Fanny |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of beads that Yoko and Fanny have
= 70 u + 50 u
= 120 u
After Yoko gives to Fanny, both of them will have the same number of beads.
The total number of beads that Yoko and Fanny have remains unchanged.
Number of beads that each of them will have
= 120 u ÷ 2
= 60 u
Number of beads that Yoko gives to Fanny
= 70 u - 60 u
= 10 u
10 u = 50
1 u = 50 ÷ 10 = 5
Total number of beads that three of them have
= 120 u + 21 u
= 141 u
Average number of beads that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 5
= 235
Answer(s): 235