Eva has 30% as many erasers as Xylia. Xylia has 140% as many erasers as Shannon. If Xylia gives 20 erasers to Shannon, both will then have an equal number of erasers. Find the average number of erasers the three of them have.

Eva	Xylia	Shannon
3x7	10x7
	7x10	5x10
21 u	70 u	50 u

30% = ³⁰₁₀₀ = ³₁₀
140% = ¹⁴⁰₁₀₀= ⁷₅

The number of erasers that Eva has is repeated.  Make the number of erasers that Eva has the same. LCM of 10 and 7 is 70.

	Xylia	Shannon	Total
Before	70 u	50 u	120 u
Change	- 10 u	+ 10 u
After	60 u	60 u	120 u

Total number of erasers that Xylia and Shannon have
= 70 u + 50 u
= 120 u

After Xylia gives to Shannon, both of them will have the same number of erasers. 

The total number of erasers that Xylia and Shannon have remains unchanged.

Number of erasers that each of them will have
= 120 u ÷ 2
= 60 u

Number of erasers that Xylia gives to Shannon
= 70 u - 60 u
= 10 u

10 u = 20

1 u = 20 ÷ 10 = 2

Total number of erasers that three of them have
= 120 u + 21 u
= 141 u

Average number of erasers that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 2
= 94

Answer(s): 94