Yoko has 30% as many stickers as Fanny. Fanny has 110% as many stickers as Irene. If Fanny gives 35 stickers to Irene, both will then have an equal number of stickers. Find the average number of stickers the three of them have.

Yoko	Fanny	Irene
3x11	10x11
	11x10	10x10
33 u	110 u	100 u

30% = ³⁰₁₀₀ = ³₁₀
110% = ¹¹⁰₁₀₀= ¹¹₁₀

The number of stickers that Yoko has is repeated.  Make the number of stickers that Yoko has the same. LCM of 10 and 11 is 110.

	Fanny	Irene	Total
Before	110 u	100 u	210 u
Change	- 5 u	+ 5 u
After	105 u	105 u	210 u

Total number of stickers that Fanny and Irene have
= 110 u + 100 u
= 210 u

After Fanny gives to Irene, both of them will have the same number of stickers. 

The total number of stickers that Fanny and Irene have remains unchanged.

Number of stickers that each of them will have
= 210 u ÷ 2
= 105 u

Number of stickers that Fanny gives to Irene
= 110 u - 105 u
= 5 u

5 u = 35

1 u = 35 ÷ 5 = 7

Total number of stickers that three of them have
= 210 u + 33 u
= 243 u

Average number of stickers that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 7
= 567

Answer(s): 567