Hazel has 30% as many stickers as Gem. Gem has 140% as many stickers as Irene. If Gem gives 80 stickers to Irene, both will then have an equal number of stickers. Find the average number of stickers the three of them have.

Hazel	Gem	Irene
3x7	10x7
	7x10	5x10
21 u	70 u	50 u

30% = ³⁰₁₀₀ = ³₁₀
140% = ¹⁴⁰₁₀₀= ⁷₅

The number of stickers that Hazel has is repeated.  Make the number of stickers that Hazel has the same. LCM of 10 and 7 is 70.

	Gem	Irene	Total
Before	70 u	50 u	120 u
Change	- 10 u	+ 10 u
After	60 u	60 u	120 u

Total number of stickers that Gem and Irene have
= 70 u + 50 u
= 120 u

After Gem gives to Irene, both of them will have the same number of stickers. 

The total number of stickers that Gem and Irene have remains unchanged.

Number of stickers that each of them will have
= 120 u ÷ 2
= 60 u

Number of stickers that Gem gives to Irene
= 70 u - 60 u
= 10 u

10 u = 80

1 u = 80 ÷ 10 = 8

Total number of stickers that three of them have
= 120 u + 21 u
= 141 u

Average number of stickers that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 8
= 376

Answer(s): 376