Yen has 25% as many beads as Tiffany. Tiffany has 130% as many beads as Jade. If Tiffany gives 54 beads to Jade, both will then have an equal number of beads. Find the average number of beads the three of them have.
Yen |
Tiffany |
Jade |
1x13 |
4x13 |
|
|
13x4 |
10x4 |
13 u |
52 u |
40 u |
25% =
25100 =
14130% =
130100=
1310The number of beads that Yen has is repeated. Make the number of beads that Yen has the same. LCM of 4 and 13 is 52.
|
Tiffany |
Jade |
Total |
Before |
52 u |
40 u |
92 u |
Change |
- 6 u |
+ 6 u |
|
After |
46 u |
46 u |
92 u |
Total number of beads that Tiffany and Jade have
= 52 u + 40 u
= 92 u
After Tiffany gives to Jade, both of them will have the same number of beads.
The total number of beads that Tiffany and Jade have remains unchanged.
Number of beads that each of them will have
= 92 u ÷ 2
= 46 u
Number of beads that Tiffany gives to Jade
= 52 u - 46 u
= 6 u
6 u = 54
1 u = 54 ÷ 6 = 9
Total number of beads that three of them have
= 92 u + 13 u
= 105 u
Average number of beads that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 9
= 315
Answer(s): 315