Joelle has 25% as many pens as Hazel. Hazel has 130% as many pens as Dana. If Hazel gives 66 pens to Dana, both will then have an equal number of pens. Find the average number of pens the three of them have.

Joelle	Hazel	Dana
1x13	4x13
	13x4	10x4
13 u	52 u	40 u

25% = ²⁵₁₀₀ = ¹₄
130% = ¹³⁰₁₀₀= ¹³₁₀

The number of pens that Joelle has is repeated.  Make the number of pens that Joelle has the same. LCM of 4 and 13 is 52.

	Hazel	Dana	Total
Before	52 u	40 u	92 u
Change	- 6 u	+ 6 u
After	46 u	46 u	92 u

Total number of pens that Hazel and Dana have
= 52 u + 40 u
= 92 u

After Hazel gives to Dana, both of them will have the same number of pens. 

The total number of pens that Hazel and Dana have remains unchanged.

Number of pens that each of them will have
= 92 u ÷ 2
= 46 u

Number of pens that Hazel gives to Dana
= 52 u - 46 u
= 6 u

6 u = 66

1 u = 66 ÷ 6 = 11

Total number of pens that three of them have
= 92 u + 13 u
= 105 u

Average number of pens that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 11
= 385

Answer(s): 385