Dana has 30% as many beads as Victoria. Victoria has 140% as many beads as Usha. If Victoria gives 40 beads to Usha, both will then have an equal number of beads. Find the average number of beads the three of them have.
Dana |
Victoria |
Usha |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of beads that Dana has is repeated. Make the number of beads that Dana has the same. LCM of 10 and 7 is 70.
|
Victoria |
Usha |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of beads that Victoria and Usha have
= 70 u + 50 u
= 120 u
After Victoria gives to Usha, both of them will have the same number of beads.
The total number of beads that Victoria and Usha have remains unchanged.
Number of beads that each of them will have
= 120 u ÷ 2
= 60 u
Number of beads that Victoria gives to Usha
= 70 u - 60 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Total number of beads that three of them have
= 120 u + 21 u
= 141 u
Average number of beads that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 4
= 188
Answer(s): 188