Nicole has 30% as many coins as Fanny. Fanny has 110% as many coins as Hilda. If Fanny gives 10 coins to Hilda, both will then have an equal number of coins. Find the average number of coins the three of them have.

Nicole	Fanny	Hilda
3x11	10x11
	11x10	10x10
33 u	110 u	100 u

30% = ³⁰₁₀₀ = ³₁₀
110% = ¹¹⁰₁₀₀= ¹¹₁₀

The number of coins that Nicole has is repeated.  Make the number of coins that Nicole has the same. LCM of 10 and 11 is 110.

	Fanny	Hilda	Total
Before	110 u	100 u	210 u
Change	- 5 u	+ 5 u
After	105 u	105 u	210 u

Total number of coins that Fanny and Hilda have
= 110 u + 100 u
= 210 u

After Fanny gives to Hilda, both of them will have the same number of coins. 

The total number of coins that Fanny and Hilda have remains unchanged.

Number of coins that each of them will have
= 210 u ÷ 2
= 105 u

Number of coins that Fanny gives to Hilda
= 110 u - 105 u
= 5 u

5 u = 10

1 u = 10 ÷ 5 = 2

Total number of coins that three of them have
= 210 u + 33 u
= 243 u

Average number of coins that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 2
= 162

Answer(s): 162