Risa has 30% as many coins as Erika. Erika has 140% as many coins as Tammy. If Erika gives 60 coins to Tammy, both will then have an equal number of coins. Find the average number of coins the three of them have.
Risa |
Erika |
Tammy |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of coins that Risa has is repeated. Make the number of coins that Risa has the same. LCM of 10 and 7 is 70.
|
Erika |
Tammy |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of coins that Erika and Tammy have
= 70 u + 50 u
= 120 u
After Erika gives to Tammy, both of them will have the same number of coins.
The total number of coins that Erika and Tammy have remains unchanged.
Number of coins that each of them will have
= 120 u ÷ 2
= 60 u
Number of coins that Erika gives to Tammy
= 70 u - 60 u
= 10 u
10 u = 60
1 u = 60 ÷ 10 = 6
Total number of coins that three of them have
= 120 u + 21 u
= 141 u
Average number of coins that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 6
= 282
Answer(s): 282