Anna has 30% as many coins as Winnie. Winnie has 110% as many coins as Cindy. If Winnie gives 60 coins to Cindy, both will then have an equal number of coins. Find the average number of coins the three of them have.
Anna |
Winnie |
Cindy |
3x11 |
10x11 |
|
|
11x10 |
10x10 |
33 u |
110 u |
100 u |
30% =
30100 =
310110% =
110100=
1110The number of coins that Anna has is repeated. Make the number of coins that Anna has the same. LCM of 10 and 11 is 110.
|
Winnie |
Cindy |
Total |
Before |
110 u |
100 u |
210 u |
Change |
- 5 u |
+ 5 u |
|
After |
105 u |
105 u |
210 u |
Total number of coins that Winnie and Cindy have
= 110 u + 100 u
= 210 u
After Winnie gives to Cindy, both of them will have the same number of coins.
The total number of coins that Winnie and Cindy have remains unchanged.
Number of coins that each of them will have
= 210 u ÷ 2
= 105 u
Number of coins that Winnie gives to Cindy
= 110 u - 105 u
= 5 u
5 u = 60
1 u = 60 ÷ 5 = 12
Total number of coins that three of them have
= 210 u + 33 u
= 243 u
Average number of coins that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 12
= 972
Answer(s): 972