Kathy has 30% as many erasers as Cindy. Cindy has 110% as many erasers as Gabby. If Cindy gives 35 erasers to Gabby, both will then have an equal number of erasers. Find the average number of erasers the three of them have.
Kathy |
Cindy |
Gabby |
3x11 |
10x11 |
|
|
11x10 |
10x10 |
33 u |
110 u |
100 u |
30% =
30100 =
310110% =
110100=
1110The number of erasers that Kathy has is repeated. Make the number of erasers that Kathy has the same. LCM of 10 and 11 is 110.
|
Cindy |
Gabby |
Total |
Before |
110 u |
100 u |
210 u |
Change |
- 5 u |
+ 5 u |
|
After |
105 u |
105 u |
210 u |
Total number of erasers that Cindy and Gabby have
= 110 u + 100 u
= 210 u
After Cindy gives to Gabby, both of them will have the same number of erasers.
The total number of erasers that Cindy and Gabby have remains unchanged.
Number of erasers that each of them will have
= 210 u ÷ 2
= 105 u
Number of erasers that Cindy gives to Gabby
= 110 u - 105 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Total number of erasers that three of them have
= 210 u + 33 u
= 243 u
Average number of erasers that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 7
= 567
Answer(s): 567