Linda has 30% as many erasers as Jaslyn. Jaslyn has 110% as many erasers as Wendy. If Jaslyn gives 55 erasers to Wendy, both will then have an equal number of erasers. Find the average number of erasers the three of them have.
Linda |
Jaslyn |
Wendy |
3x11 |
10x11 |
|
|
11x10 |
10x10 |
33 u |
110 u |
100 u |
30% =
30100 =
310110% =
110100=
1110The number of erasers that Linda has is repeated. Make the number of erasers that Linda has the same. LCM of 10 and 11 is 110.
|
Jaslyn |
Wendy |
Total |
Before |
110 u |
100 u |
210 u |
Change |
- 5 u |
+ 5 u |
|
After |
105 u |
105 u |
210 u |
Total number of erasers that Jaslyn and Wendy have
= 110 u + 100 u
= 210 u
After Jaslyn gives to Wendy, both of them will have the same number of erasers.
The total number of erasers that Jaslyn and Wendy have remains unchanged.
Number of erasers that each of them will have
= 210 u ÷ 2
= 105 u
Number of erasers that Jaslyn gives to Wendy
= 110 u - 105 u
= 5 u
5 u = 55
1 u = 55 ÷ 5 = 11
Total number of erasers that three of them have
= 210 u + 33 u
= 243 u
Average number of erasers that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 11
= 891
Answer(s): 891