Hilda has 30% as many stickers as Kimberly. Kimberly has 140% as many stickers as Emily. If Kimberly gives 20 stickers to Emily, both will then have an equal number of stickers. Find the average number of stickers the three of them have.
Hilda |
Kimberly |
Emily |
3x7 |
10x7 |
|
|
7x10 |
5x10 |
21 u |
70 u |
50 u |
30% =
30100 =
310140% =
140100=
75The number of stickers that Hilda has is repeated. Make the number of stickers that Hilda has the same. LCM of 10 and 7 is 70.
|
Kimberly |
Emily |
Total |
Before |
70 u |
50 u |
120 u |
Change |
- 10 u |
+ 10 u |
|
After |
60 u |
60 u |
120 u |
Total number of stickers that Kimberly and Emily have
= 70 u + 50 u
= 120 u
After Kimberly gives to Emily, both of them will have the same number of stickers.
The total number of stickers that Kimberly and Emily have remains unchanged.
Number of stickers that each of them will have
= 120 u ÷ 2
= 60 u
Number of stickers that Kimberly gives to Emily
= 70 u - 60 u
= 10 u
10 u = 20
1 u = 20 ÷ 10 = 2
Total number of stickers that three of them have
= 120 u + 21 u
= 141 u
Average number of stickers that each of them have
= 141 u ÷ 3
= 47 u
= 47 x 2
= 94
Answer(s): 94