Victoria has 30% as many coins as Hilda. Hilda has 110% as many coins as Vanessa. If Hilda gives 60 coins to Vanessa, both will then have an equal number of coins. Find the average number of coins the three of them have.

Victoria	Hilda	Vanessa
3x11	10x11
	11x10	10x10
33 u	110 u	100 u

30% = ³⁰₁₀₀ = ³₁₀
110% = ¹¹⁰₁₀₀= ¹¹₁₀

The number of coins that Victoria has is repeated.  Make the number of coins that Victoria has the same. LCM of 10 and 11 is 110.

	Hilda	Vanessa	Total
Before	110 u	100 u	210 u
Change	- 5 u	+ 5 u
After	105 u	105 u	210 u

Total number of coins that Hilda and Vanessa have
= 110 u + 100 u
= 210 u

After Hilda gives to Vanessa, both of them will have the same number of coins. 

The total number of coins that Hilda and Vanessa have remains unchanged.

Number of coins that each of them will have
= 210 u ÷ 2
= 105 u

Number of coins that Hilda gives to Vanessa
= 110 u - 105 u
= 5 u

5 u = 60

1 u = 60 ÷ 5 = 12

Total number of coins that three of them have
= 210 u + 33 u
= 243 u

Average number of coins that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 12
= 972

Answer(s): 972