Anna has 25% as many pens as Jen. Jen has 130% as many pens as Jean. If Jen gives 30 pens to Jean, both will then have an equal number of pens. Find the average number of pens the three of them have.
Anna |
Jen |
Jean |
1x13 |
4x13 |
|
|
13x4 |
10x4 |
13 u |
52 u |
40 u |
25% =
25100 =
14130% =
130100=
1310The number of pens that Anna has is repeated. Make the number of pens that Anna has the same. LCM of 4 and 13 is 52.
|
Jen |
Jean |
Total |
Before |
52 u |
40 u |
92 u |
Change |
- 6 u |
+ 6 u |
|
After |
46 u |
46 u |
92 u |
Total number of pens that Jen and Jean have
= 52 u + 40 u
= 92 u
After Jen gives to Jean, both of them will have the same number of pens.
The total number of pens that Jen and Jean have remains unchanged.
Number of pens that each of them will have
= 92 u ÷ 2
= 46 u
Number of pens that Jen gives to Jean
= 52 u - 46 u
= 6 u
6 u = 30
1 u = 30 ÷ 6 = 5
Total number of pens that three of them have
= 92 u + 13 u
= 105 u
Average number of pens that each of them have
= 105 u ÷ 3
= 35 u
= 35 x 5
= 175
Answer(s): 175