Yen has 30% as many coins as Anna. Anna has 110% as many coins as Linda. If Anna gives 55 coins to Linda, both will then have an equal number of coins. Find the average number of coins the three of them have.

Yen	Anna	Linda
3x11	10x11
	11x10	10x10
33 u	110 u	100 u

30% = ³⁰₁₀₀ = ³₁₀
110% = ¹¹⁰₁₀₀= ¹¹₁₀

The number of coins that Yen has is repeated.  Make the number of coins that Yen has the same. LCM of 10 and 11 is 110.

	Anna	Linda	Total
Before	110 u	100 u	210 u
Change	- 5 u	+ 5 u
After	105 u	105 u	210 u

Total number of coins that Anna and Linda have
= 110 u + 100 u
= 210 u

After Anna gives to Linda, both of them will have the same number of coins. 

The total number of coins that Anna and Linda have remains unchanged.

Number of coins that each of them will have
= 210 u ÷ 2
= 105 u

Number of coins that Anna gives to Linda
= 110 u - 105 u
= 5 u

5 u = 55

1 u = 55 ÷ 5 = 11

Total number of coins that three of them have
= 210 u + 33 u
= 243 u

Average number of coins that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 11
= 891

Answer(s): 891