Wendy has 30% as many stamps as Jaslyn. Jaslyn has 110% as many stamps as Irene. If Jaslyn gives 55 stamps to Irene, both will then have an equal number of stamps. Find the average number of stamps the three of them have.
Wendy |
Jaslyn |
Irene |
3x11 |
10x11 |
|
|
11x10 |
10x10 |
33 u |
110 u |
100 u |
30% =
30100 =
310110% =
110100=
1110The number of stamps that Wendy has is repeated. Make the number of stamps that Wendy has the same. LCM of 10 and 11 is 110.
|
Jaslyn |
Irene |
Total |
Before |
110 u |
100 u |
210 u |
Change |
- 5 u |
+ 5 u |
|
After |
105 u |
105 u |
210 u |
Total number of stamps that Jaslyn and Irene have
= 110 u + 100 u
= 210 u
After Jaslyn gives to Irene, both of them will have the same number of stamps.
The total number of stamps that Jaslyn and Irene have remains unchanged.
Number of stamps that each of them will have
= 210 u ÷ 2
= 105 u
Number of stamps that Jaslyn gives to Irene
= 110 u - 105 u
= 5 u
5 u = 55
1 u = 55 ÷ 5 = 11
Total number of stamps that three of them have
= 210 u + 33 u
= 243 u
Average number of stamps that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 11
= 891
Answer(s): 891