Jane has 30% as many coins as Lucy. Lucy has 110% as many coins as Yoko. If Lucy gives 60 coins to Yoko, both will then have an equal number of coins. Find the average number of coins the three of them have.

Jane	Lucy	Yoko
3x11	10x11
	11x10	10x10
33 u	110 u	100 u

30% = ³⁰₁₀₀ = ³₁₀
110% = ¹¹⁰₁₀₀= ¹¹₁₀

The number of coins that Jane has is repeated.  Make the number of coins that Jane has the same. LCM of 10 and 11 is 110.

	Lucy	Yoko	Total
Before	110 u	100 u	210 u
Change	- 5 u	+ 5 u
After	105 u	105 u	210 u

Total number of coins that Lucy and Yoko have
= 110 u + 100 u
= 210 u

After Lucy gives to Yoko, both of them will have the same number of coins. 

The total number of coins that Lucy and Yoko have remains unchanged.

Number of coins that each of them will have
= 210 u ÷ 2
= 105 u

Number of coins that Lucy gives to Yoko
= 110 u - 105 u
= 5 u

5 u = 60

1 u = 60 ÷ 5 = 12

Total number of coins that three of them have
= 210 u + 33 u
= 243 u

Average number of coins that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 12
= 972

Answer(s): 972