Raeann has 30% as many coins as Linda. Linda has 110% as many coins as Rachel. If Linda gives 25 coins to Rachel, both will then have an equal number of coins. Find the average number of coins the three of them have.
Raeann |
Linda |
Rachel |
3x11 |
10x11 |
|
|
11x10 |
10x10 |
33 u |
110 u |
100 u |
30% =
30100 =
310110% =
110100=
1110The number of coins that Raeann has is repeated. Make the number of coins that Raeann has the same. LCM of 10 and 11 is 110.
|
Linda |
Rachel |
Total |
Before |
110 u |
100 u |
210 u |
Change |
- 5 u |
+ 5 u |
|
After |
105 u |
105 u |
210 u |
Total number of coins that Linda and Rachel have
= 110 u + 100 u
= 210 u
After Linda gives to Rachel, both of them will have the same number of coins.
The total number of coins that Linda and Rachel have remains unchanged.
Number of coins that each of them will have
= 210 u ÷ 2
= 105 u
Number of coins that Linda gives to Rachel
= 110 u - 105 u
= 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Total number of coins that three of them have
= 210 u + 33 u
= 243 u
Average number of coins that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 5
= 405
Answer(s): 405