Roshel has 30% as many erasers as Winnie. Winnie has 110% as many erasers as Vanessa. If Winnie gives 10 erasers to Vanessa, both will then have an equal number of erasers. Find the average number of erasers the three of them have.
Roshel |
Winnie |
Vanessa |
3x11 |
10x11 |
|
|
11x10 |
10x10 |
33 u |
110 u |
100 u |
30% =
30100 =
310110% =
110100=
1110The number of erasers that Roshel has is repeated. Make the number of erasers that Roshel has the same. LCM of 10 and 11 is 110.
|
Winnie |
Vanessa |
Total |
Before |
110 u |
100 u |
210 u |
Change |
- 5 u |
+ 5 u |
|
After |
105 u |
105 u |
210 u |
Total number of erasers that Winnie and Vanessa have
= 110 u + 100 u
= 210 u
After Winnie gives to Vanessa, both of them will have the same number of erasers.
The total number of erasers that Winnie and Vanessa have remains unchanged.
Number of erasers that each of them will have
= 210 u ÷ 2
= 105 u
Number of erasers that Winnie gives to Vanessa
= 110 u - 105 u
= 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Total number of erasers that three of them have
= 210 u + 33 u
= 243 u
Average number of erasers that each of them have
= 243 u ÷ 3
= 81 u
= 81 x 2
= 162
Answer(s): 162