Liam and Perry had some beads in the ratio of 9 : 8. Perry and Daniel had some beads in the ratio of 4 : 1. Liam sold 35 beads to Daniel and ended up with half the number of beads Perry had. How many beads did Daniel have in the end?
| Liam |
Perry |
Daniel |
| 9x1 |
8x1 |
|
| |
4x2 |
1x2 |
| 9 u |
8 u |
2 u |
The number of beads that Perry had at first is repeated. Make the number of beads that Perry had at first the same. LCM of 8 and 4 is 8.
| |
Liam |
Perry |
Daniel |
| Before |
9 u |
8 u |
2 u |
| Change |
- 35 |
|
+ 35 |
| After |
4 u |
8 u |
2 u + 35 |
Number of beads that Liam had in the end
= 8 u ÷ 2
= 4 u
Number of beads that Liam sold to Daniel
= 9 u - 4 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of beads that Daniel had in the end
= 2 u + 35
= 2 x 7 + 35
= 14 + 35
= 49
Answer(s): 49
