Perry and Paul had some pens in the ratio of 7 : 6. Paul and Ahmad had some pens in the ratio of 5 : 2. Perry sold 220 pens to Ahmad and ended up with half the number of pens Paul had. How many pens did Ahmad have in the end?
| Perry |
Paul |
Ahmad |
| 7x5 |
6x5 |
|
| |
5x6 |
2x6 |
| 35 u |
30 u |
12 u |
The number of pens that Paul had at first is repeated. Make the number of pens that Paul had at first the same. LCM of 6 and 5 is 30.
| |
Perry |
Paul |
Ahmad |
| Before |
35 u |
30 u |
12 u |
| Change |
- 220 |
|
+ 220 |
| After |
15 u |
30 u |
12 u + 220 |
Number of pens that Perry had in the end
= 30 u ÷ 2
= 15 u
Number of pens that Perry sold to Ahmad
= 35 u - 15 u
= 20 u
20 u = 220
1 u = 220 ÷ 20 = 11
Number of pens that Ahmad had in the end
= 12 u + 220
= 12 x 11 + 220
= 132 + 220
= 352
Answer(s): 352
