Zeph and Michael had some stickers in the ratio of 8 : 3. Michael and Cody had some stickers in the ratio of 2 : 1. Zeph sold 26 stickers to Cody and ended up with half the number of stickers Michael had. How many stickers did Cody have in the end?
| Zeph |
Michael |
Cody |
| 8x2 |
3x2 |
|
| |
2x3 |
1x3 |
| 16 u |
6 u |
3 u |
The number of stickers that Michael had at first is repeated. Make the number of stickers that Michael had at first the same. LCM of 3 and 2 is 6.
| |
Zeph |
Michael |
Cody |
| Before |
16 u |
6 u |
3 u |
| Change |
- 26 |
|
+ 26 |
| After |
3 u |
6 u |
3 u + 26 |
Number of stickers that Zeph had in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Zeph sold to Cody
= 16 u - 3 u
= 13 u
13 u = 26
1 u = 26 ÷ 13 = 2
Number of stickers that Cody had in the end
= 3 u + 26
= 3 x 2 + 26
= 6 + 26
= 32
Answer(s): 32
