Japheth and Archie had some pens in the ratio of 9 : 7. Archie and Albert had some pens in the ratio of 10 : 7. Japheth sold 220 pens to Albert and ended up with half the number of pens Archie had. How many pens did Albert have in the end?
| Japheth |
Archie |
Albert |
| 9x10 |
7x10 |
|
| |
10x7 |
7x7 |
| 90 u |
70 u |
49 u |
The number of pens that Archie had at first is repeated. Make the number of pens that Archie had at first the same. LCM of 7 and 10 is 70.
| |
Japheth |
Archie |
Albert |
| Before |
90 u |
70 u |
49 u |
| Change |
- 220 |
|
+ 220 |
| After |
35 u |
70 u |
49 u + 220 |
Number of pens that Japheth had in the end
= 70 u ÷ 2
= 35 u
Number of pens that Japheth sold to Albert
= 90 u - 35 u
= 55 u
55 u = 220
1 u = 220 ÷ 55 = 4
Number of pens that Albert had in the end
= 49 u + 220
= 49 x 4 + 220
= 196 + 220
= 416
Answer(s): 416
