Mark and Peter had some stickers in the ratio of 4 : 1. Peter and David had some stickers in the ratio of 8 : 7. Mark sold 224 stickers to David and ended up with half the number of stickers Peter had. How many stickers did David have in the end?
| Mark |
Peter |
David |
| 4x8 |
1x8 |
|
| |
8x1 |
7x1 |
| 32 u |
8 u |
7 u |
The number of stickers that Peter had at first is repeated. Make the number of stickers that Peter had at first the same. LCM of 1 and 8 is 8.
| |
Mark |
Peter |
David |
| Before |
32 u |
8 u |
7 u |
| Change |
- 224 |
|
+ 224 |
| After |
4 u |
8 u |
7 u + 224 |
Number of stickers that Mark had in the end
= 8 u ÷ 2
= 4 u
Number of stickers that Mark sold to David
= 32 u - 4 u
= 28 u
28 u = 224
1 u = 224 ÷ 28 = 8
Number of stickers that David had in the end
= 7 u + 224
= 7 x 8 + 224
= 56 + 224
= 280
Answer(s): 280
