Tim and Wesley had some buttons in the ratio of 7 : 6. Wesley and Bryan had some buttons in the ratio of 7 : 4. Tim sold 112 buttons to Bryan and ended up with half the number of buttons Wesley had. How many buttons did Bryan have in the end?
| Tim |
Wesley |
Bryan |
| 7x7 |
6x7 |
|
| |
7x6 |
4x6 |
| 49 u |
42 u |
24 u |
The number of buttons that Wesley had at first is repeated. Make the number of buttons that Wesley had at first the same. LCM of 6 and 7 is 42.
| |
Tim |
Wesley |
Bryan |
| Before |
49 u |
42 u |
24 u |
| Change |
- 112 |
|
+ 112 |
| After |
21 u |
42 u |
24 u + 112 |
Number of buttons that Tim had in the end
= 42 u ÷ 2
= 21 u
Number of buttons that Tim sold to Bryan
= 49 u - 21 u
= 28 u
28 u = 112
1 u = 112 ÷ 28 = 4
Number of buttons that Bryan had in the end
= 24 u + 112
= 24 x 4 + 112
= 96 + 112
= 208
Answer(s): 208
