Gabriel and Bobby had some stickers in the ratio of 8 : 1. Bobby and Caden had some stickers in the ratio of 10 : 9. Gabriel sold 525 stickers to Caden and ended up with half the number of stickers Bobby had. How many stickers did Caden have in the end?
| Gabriel |
Bobby |
Caden |
| 8x10 |
1x10 |
|
| |
10x1 |
9x1 |
| 80 u |
10 u |
9 u |
The number of stickers that Bobby had at first is repeated. Make the number of stickers that Bobby had at first the same. LCM of 1 and 10 is 10.
| |
Gabriel |
Bobby |
Caden |
| Before |
80 u |
10 u |
9 u |
| Change |
- 525 |
|
+ 525 |
| After |
5 u |
10 u |
9 u + 525 |
Number of stickers that Gabriel had in the end
= 10 u ÷ 2
= 5 u
Number of stickers that Gabriel sold to Caden
= 80 u - 5 u
= 75 u
75 u = 525
1 u = 525 ÷ 75 = 7
Number of stickers that Caden had in the end
= 9 u + 525
= 9 x 7 + 525
= 63 + 525
= 588
Answer(s): 588
