Pierre and Warren had some cards in the ratio of 4 : 3. Warren and Andy had some cards in the ratio of 8 : 1. Pierre sold 120 cards to Andy and ended up with half the number of cards Warren had. How many cards did Andy have in the end?
| Pierre |
Warren |
Andy |
| 4x8 |
3x8 |
|
| |
8x3 |
1x3 |
| 32 u |
24 u |
3 u |
The number of cards that Warren had at first is repeated. Make the number of cards that Warren had at first the same. LCM of 3 and 8 is 24.
| |
Pierre |
Warren |
Andy |
| Before |
32 u |
24 u |
3 u |
| Change |
- 120 |
|
+ 120 |
| After |
12 u |
24 u |
3 u + 120 |
Number of cards that Pierre had in the end
= 24 u ÷ 2
= 12 u
Number of cards that Pierre sold to Andy
= 32 u - 12 u
= 20 u
20 u = 120
1 u = 120 ÷ 20 = 6
Number of cards that Andy had in the end
= 3 u + 120
= 3 x 6 + 120
= 18 + 120
= 138
Answer(s): 138
