Sean and Fabian had some coins in the ratio of 5 : 1. Fabian and Harry had some coins in the ratio of 4 : 3. Sean sold 180 coins to Harry and ended up with half the number of coins Fabian had. How many coins did Harry have in the end?
| Sean |
Fabian |
Harry |
| 5x4 |
1x4 |
|
| |
4x1 |
3x1 |
| 20 u |
4 u |
3 u |
The number of coins that Fabian had at first is repeated. Make the number of coins that Fabian had at first the same. LCM of 1 and 4 is 4.
| |
Sean |
Fabian |
Harry |
| Before |
20 u |
4 u |
3 u |
| Change |
- 180 |
|
+ 180 |
| After |
2 u |
4 u |
3 u + 180 |
Number of coins that Sean had in the end
= 4 u ÷ 2
= 2 u
Number of coins that Sean sold to Harry
= 20 u - 2 u
= 18 u
18 u = 180
1 u = 180 ÷ 18 = 10
Number of coins that Harry had in the end
= 3 u + 180
= 3 x 10 + 180
= 30 + 180
= 210
Answer(s): 210
