Andy and Glen had some coins in the ratio of 7 : 6. Glen and Julian had some coins in the ratio of 9 : 2. Andy sold 132 coins to Julian and ended up with half the number of coins Glen had. How many coins did Julian have in the end?
| Andy |
Glen |
Julian |
| 7x3 |
6x3 |
|
| |
9x2 |
2x2 |
| 21 u |
18 u |
4 u |
The number of coins that Glen had at first is repeated. Make the number of coins that Glen had at first the same. LCM of 6 and 9 is 18.
| |
Andy |
Glen |
Julian |
| Before |
21 u |
18 u |
4 u |
| Change |
- 132 |
|
+ 132 |
| After |
9 u |
18 u |
4 u + 132 |
Number of coins that Andy had in the end
= 18 u ÷ 2
= 9 u
Number of coins that Andy sold to Julian
= 21 u - 9 u
= 12 u
12 u = 132
1 u = 132 ÷ 12 = 11
Number of coins that Julian had in the end
= 4 u + 132
= 4 x 11 + 132
= 44 + 132
= 176
Answer(s): 176
